In the diagram, $ABCD$ and $DEFG$ are squares on a flat surface. Show that \(\angle ADE = \

Question

In the diagram, $ABCD$ and $DEFG$ are squares on a flat surface. Show that $\angle ADE = \angle CDG$. Prove that $\Delta ADE$ is congruent to $\Delta CDG$.

Accepted Answer

$\text{(i)}\ \angle ADE=\angle CDG$ $\text{(ii)}\ \triangle ADE\cong\triangle CDG\text{ (SAS)}$

IP2U8 Exercise Q1

IP2U8 Exercise Q1

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