In $\Delta ABC$, $AB=7.5$m and $\angle ACB=90{}^\circ $. $X$ lies on $CA$ such that \

Question

In $\Delta ABC$, $AB=7.5$m and $\angle ACB=90{}^\circ $. $X$ lies on $CA$ such that $XB=3$m and $\angle XBC=43{}^\circ $. Find $\angle BAC$, the length of $XA$.

Accepted Answer

(i) $17.0^\circ$ (ii) $5.13$ m

IP2U7 7.2 Worked Example 2

IP2U7 7.2 Worked Example 2

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Solution:

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