IP2U4 Exercise Q8

IP2U4 Exercise Q8

Express \({{x}^{2}}+4x+7\) in the form of \({{\left( x+a \right)}^{2}}+b\).
Hence, solve the equation \({{x}^{2}}+4x+7=12\).

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Answer:(i) \(a=2\), \(b=3\) (ii) \(x=1\) or \(x=-5\)

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