IP2U14 HOT Q3

IP2U14 HOT Q3

IP 2

\(ABCD\) is a convex quadrilateral such that \(\angle BAD=56^\circ\) and \(\angle ADC=108^\circ\). \(DC\) is produced to \(P\) such that \(\angle BPD=52^\circ\) and \(BC\) bisects \(\angle ABP\). If \(\angle BDC=35^\circ\), find \(\angle ACB\) and \(\angle ACP\).

Video Solution:

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:\(\angle ACB=73^\circ\), \(\angle ACP=129^\circ\)

Need help? Join our IP Math tuition programme.

Learn more