IP2U14 HOT Q3

IP2U14 HOT Q3

IP 2

\(ABCD\) is a quadrilateral such that \(\angle BAD={{56}^{{}^\circ }}\) and \(\angle ADC={{108}^{{}^\circ }}\). \(DC\) is produced to \(P\) such that \(\angle BPD={{52}^{{}^\circ }}\) and \(BC\) bisects \(\angle ABP\). If \(\angle BDC={{35}^{{}^\circ }}\), find \(\angle ACB\) and \(\angle ACP\).

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Answer:\(\angle ACB=73^\circ\), \(\angle ACP=129^\circ\)

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