IP2U14 HOT Q2

IP2U14 HOT Q2

IP 2

\(P\), \(Q\) and \(R\) are points that lie on a circle. The tangent to the circle at \(R\) meets the line \(PQ\) produced at \(S\). Point \(X\) is on the line \(PQ\) such that \(RX\) bisects \(\angle PRQ\). Prove that \(RS=XS\).

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Answer:Proved: \(RS=XS\)

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