Triangle solver

<p>In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.</p>
<p>It is given that&nbsp;\(b^2 - a^2 = ac\), show that&nbsp;\(\frac{a}{b} = \frac{\cos A}{1 + \cos B}\).</p>

In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.

It is given that \(b^2 - a^2 = ac\), show that \(\frac{a}{b} = \frac{\cos A}{1 + \cos B}\).

IP2 U12 HOT Q4

IP2 U12 HOT Q4

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