In triangle $ABC$, $a$, $b$ and $c$ are the opposite sides of the interior angles $A$, \(B

Question

In triangle $ABC$, $a$, $b$ and $c$ are the opposite sides of the interior angles $A$, $B$ and $C$, respectively. It is given that $c = 2$ and $b = \sqrt{2}a$, show that the maximum area of triangle $ABC$ is $2\sqrt{2}$. Hence find the exact value of $a$ when the area of triangle is maximised.

Accepted Answer

$a=2\sqrt{3}$

IP2 U12 HOT Q3

IP2 U12 HOT Q3

Video Solution:

Solution:

Solution locked