In triangle $ABC$, $a$, $b$ and $c$ are the opposite sides of the interior angles $A$, \(B

Question

In triangle $ABC$, $a$, $b$ and $c$ are the opposite sides of the interior angles $A$, $B$ and $C$, respectively. It is given that $3a = 2b$, find the value of $\frac{2 \sin^2 B - \sin^2 A}{\sin^2 A}.$

Accepted Answer

$\frac{7}{2}$

IP2 U12 HOT Q1

IP2 U12 HOT Q1

Video Solution:

Solution:

Solution locked