IP2 U12 HOT Q1

IP2 U12 HOT Q1

IP 2

In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.

It is given that \(3a = 2b\), find the value of \(\frac{2 \sin^2 B - \sin^2 A}{\sin^2 A}.\)

Video Solution:

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:\(\frac{7}{2}\)

Need help? Join our E-Maths tuition for O-Level success.

Learn more