In triangle \(ABC\), \(a\), \(b\) and \(c\) are the opposite sides of the interior angles \(A\), \(B\) and \(C\), respectively.
It is given that \(3a = 2b\), find the value of \(\frac{2 \sin^2 B - \sin^2 A}{\sin^2 A}.\)
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