Solve the inequality $-2(3 + x) \le \frac{2x - 3}{2}

Question

Solve the inequality $-2(3 + x) \le \frac{2x - 3}{2} < \frac{17 - 7x}{6}$ and represent the solution on a number line.[5] Hence, state the minimum value of $x^2$, which satisfy the above inequality.[1]

Accepted Answer

(i) $-\frac32\le x<2$, closed at $-\frac32$ and open at $2$. (ii) $0$.

IP2 Class Test (May 2025) Q9 (2025 RGS Y3 CBA1 Q2)

IP2 Class Test (May 2025) Q9 (2025 RGS Y3 CBA1 Q2)

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