IP1U5 5.4 Exercise Q6

IP1U5 5.4 Exercise Q6

  1. Given that \(p=T\sqrt{\frac{p+1}{x}}\), express \(x\) in terms of \(p\) and \(T\).
  2. Hence, find the value of \(x\) when \(p=-5\), \(T=2\).

Correction to part (b): determine whether a real value of \(x\) exists for the stated values, and check any candidate in the original formula. The square root denotes its principal, non-negative value.

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Answer:(a) \(x=\frac{T^2(p+1)}{p^2}\), \(p\ne0\) (b) No real solution for the stated values.

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