IP1U4 SWI (Algebraic Identities) Q18

IP1U4 SWI (Algebraic Identities) Q18

IP 1

Factorise completely

\(a^4 - \frac{1}{b^4}\)
\(75a^3b^2 - 108ab^4\)
\(25(x+y)^2 - 16(x-y)^2\)
\(3a^5 - 48a^3\)

Video Solution:

Video solution locked

A free account saves your progress; this video needs a course plan.

Create free account Sign in Get the E Math course · from S$29.98/mo

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Create free account Sign in Get the E Math course · from S$29.98/mo E Math tuition

Create a free account to practise similar questions.

Create free account Sign in Get the E Math course · from S$29.98/mo E Math tuition

Answer:(i) \(\left(a^2+\frac1{b^2}\right)\left(a+\frac1b\right)\left(a-\frac1b\right)\) (ii) \(3ab^2(5a+6b)(5a-6b)\) (iii) \((9x+y)(x+9y)\) (iv) \(3a^3(a+4)(a-4)\)

Need help? Join our E-Maths tuition for O-Level success.