IP1U13 HOT Q2

IP1U13 HOT Q2

TGM Original Questions

Editorial clarification: the supplied solution assumes that \(E\) is the midpoint of \(BC\), so \(CE=3\text{ cm}\). This is not stated or marked in the supplied diagram. Part (a) is determined without it; the answers to parts (b)–(e) below are conditional on this intended midpoint assumption.

In the figure, \(ABCD\) is a square, where arcs \(BD\), \(EF\) are quadrants and arc \(BC\) is a semicircle, such that \(ABCD\) is fragmented into five regions. Let \(①, ②, ③, ④\) and \(⑤\) denote the area of each corresponding region. Find, leaving your answers in terms of \(\pi\),

  1. the area denoted by \(②+⑤\),
  2. the area denoted by \(②+③\),
  3. the ratio of the area denoted by \(②+③\) to the area denoted by \(④+⑤\),
  4. the area denoted by \(②-④\),
  5. the area denoted by \(①+③-⑤\).

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Answer:Assuming E is the midpoint of BC for parts (b)–(e): (a) \(\dfrac{9}{2}\pi\text{ cm}^2\) (b) \(\dfrac{27}{4}\pi\text{ cm}^2\) (c) \(3:1\) (d) \(\dfrac{9}{4}\pi\text{ cm}^2\) (e) \(\left(36-\dfrac{27}{4}\pi\right)\text{ cm}^2\)

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