In the figure below, triangle $ABC$ is an isosceles triangle, where $AB=AC$ and \(\angle BA

Question

In the figure below, triangle $ABC$ is an isosceles triangle, where $AB=AC$ and $\angle BAC={{20}^{\circ }}$. Given that $D$ is a point on $AD$, such that $AD=BC$, find $\angle ADC$. In the figure below, triangle $ABC$ is an isosceles triangle, where $AB=AC$ and $\angle BAC={{20}^{\circ }}$. Given that $D$ is a point on $AB$, $E$ is a point on $AC$ such that $\angle BCD={{60}^{\circ }}$ and $\angle CBE={{50}^{\circ }}$, find $\angle CDE$.

Accepted Answer

$\angle ACD = 10°$; $\angle ADC = 150°$

IP1U12 HOT Q4

IP1U12 HOT Q4

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