Two quantities, $\left( x+1 \right)$ and $(y-2)$ are in inverse proportion. Values of $x$ and

Question

Two quantities, $\left( x+1 \right)$ and $(y-2)$ are in inverse proportion. Values of $x$ and $y$ are shown in the table below. $x$$1$$3$$b$ $y$$10$$a$$30$ Find the equation connecting $\left( x+1 \right)$ and $(y-2)$. Hence, find the values of $a$ and $b$.

Accepted Answer

(a) $x + 1 = \frac{16}{(y-2)}$, (b) $a = 6, b = -\frac{3}{7}$

Inverse Variation Involving Linear Expressions

Inverse Variation Involving Linear Expressions

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