Inverse-square acceleration

Inverse-square acceleration

Secondary 4
6 marks
Original parallel to supplied A Math Kinematics references

A particle passes through \(O\) at time \(t=0\) with velocity \(1\text{ m s}^{-1}\). Its acceleration is \(a=\dfrac{6}{(t+1)^2}\text{ m s}^{-2}\), where \(t\geq0\).

  1. Find the velocity of the particle in terms of \(t\).[2]
  2. Hence find its displacement from \(O\) in terms of \(t\).[2]
  3. Find the distance travelled in the first \(3\) seconds.[2]

Solution:

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Answer:(i) \(v=7-\dfrac6{t+1}\text{ m s}^{-1}\) (ii) \(s=7t-6\ln(t+1)\text{ m}\) (iii) \(21-6\ln4\text{ m}\)

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