Show that $\frac{1-\cos 2x}{1+\cos 2x} = \sec^2 x - 1$. Hence, find \(\displaystyle\displayst

Question

Show that $\frac{1-\cos 2x}{1+\cos 2x} = \sec^2 x - 1$. Hence, find $\displaystyle\displaystyle \displaystyle\int \frac{4-4\cos 2x}{1+\cos 2x} \, \mathrm{d}x$.

Accepted Answer

$4\tan x-4x+C$

Integration - Integrable Forms of Trigonometric Functions

Integration - Integrable Forms of Trigonometric Functions

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