<p>In a formula containing division by \(a\), assume \(a\ne0\). If&nbsp;\(a=0\), integrate the resulting constant separately, provided it is defined. Work only on intervals where the original integrand is real and defined; use \(\ln|ax+b|\) for a reciprocal linear integrand.</p>
<div class="content-block content-block--table"><div class="table-container"><table style="width: 100%;"><tbody><tr style="height: 70px;"><td rowspan="2" style="height: 70px; min-height: 70px; text-align: center; --cell-justify: center"><p>\(\int e^x \mathrm{d}x = e^x + c\)</p></td><td rowspan="2" style="height: 70px; min-height: 70px; text-align: center; --cell-justify: center"><p>\(\int e^{ax+b} \mathrm{d}x = \frac{1}{a}e^{ax+b} + c\)</p></td></tr><tr style="height: 40px;"></tr></tbody></table></div></div>

<p>\(\int e^x \mathrm{d}x = e^x + c\)</p>

<p>\(\int e^{ax+b} \mathrm{d}x = \frac{1}{a}e^{ax+b} + c\)</p>

In a formula containing division by \(a\), assume \(a\ne0\). If \(a=0\), integrate the resulting constant separately, provided it is defined. Work only on intervals where the original integrand is real and defined; use \(\ln|ax+b|\) for a reciprocal linear integrand.

Integration - Integration of Exponential Functions

Integration - Integration of Exponential Functions

\(\int e^x \mathrm{d}x = e^x + c\)	\(\int e^{ax+b} \mathrm{d}x = \frac{1}{a}e^{ax+b} + c\)