<p>Integrate the following expressions with respect to \(x\).</p>
<ol class="abc-list"><li><div class="list-item-paragraph">\(\displaystyle\int \mathrm{e}^{1+4x} \, \mathrm{d}x\)</div></li><li><div class="list-item-paragraph">\(\displaystyle\int (\mathrm{e}^{2-x}-1)^2 \, \mathrm{d}x\)</div></li><li><div class="list-item-paragraph">\(\displaystyle\int \frac{(2\mathrm{e}^{-x}+\mathrm{e}^x)^2}{\mathrm{e}^x} \, \mathrm{d}x\)</div></li><li><div class="list-item-paragraph">\(\displaystyle\int \frac{(\mathrm{e}^{\pi x- 1}-\mathrm{e}^x)^2}{\mathrm{e}^{2x}} \, \mathrm{d}x\)</div></li></ol>
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<ol class="abc-list"></ol>

Integrate the following expressions with respect to \(x\).

\[\displaystyle\displaystyle \displaystyle\int \mathrm{e}^{1+4x} \, \mathrm{d}x\]

\(\displaystyle\displaystyle \displaystyle\int \mathrm{e}^{1+4x} \, \mathrm{d}x\)

\[\displaystyle\displaystyle \displaystyle\int (\mathrm{e}^{2-x}-1)^2 \, \mathrm{d}x\]

\(\displaystyle\displaystyle \displaystyle\int (\mathrm{e}^{2-x}-1)^2 \, \mathrm{d}x\)

\[\displaystyle\displaystyle \displaystyle\int \frac{(2\mathrm{e}^{-x}+\mathrm{e}^x)^2}{\mathrm{e}^x} \, \mathrm{d}x\]

\(\displaystyle\displaystyle \displaystyle\int \frac{(2\mathrm{e}^{-x}+\mathrm{e}^x)^2}{\mathrm{e}^x} \, \mathrm{d}x\)

\(\displaystyle\displaystyle \displaystyle\int \frac{(\mathrm{e}^{\pi x- 1}-\mathrm{e}^x)^2}{\mathrm{e}^{2x}} \, \mathrm{d}x\)

Integration Techniques

Integration Techniques

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