Show that \(\frac{\mathrm{d}}{\mathrm{d}x} \left[ (2x-1)\sqrt{x+3} \right] = \frac{6x+11}{2\sqrt{x+3}}\). Hence, find \(\displaystyle\int \frac{6x+11}{\sqrt{x+3}} \, \mathrm{d}x\).
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