Integration of Inverse Trigonometric Function Involving Modulus

Integration of Inverse Trigonometric Function Involving Modulus

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  1. Using integration by parts, find \(\displaystyle\displaystyle \displaystyle\int{{{\sin }^{-1}}}2x\ \mathrm{d}x\).
  2. Hence evaluate \(\displaystyle\displaystyle \displaystyle\int_{-\frac{1}{2}}^{\frac{1}{4}}{\left| {{\sin }^{-1}}2x \right|}\ \mathrm{d}x\) exactly.

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Answer:(i) \(x\sin^{-1}(2x) + \frac{1}{2}\sqrt{1-4x^2} + C\) (ii) \(\frac{7}{24}\pi + \frac{\sqrt{3}}{4} - 1\)

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