Water flow through a parabolic channel

Water flow through a parabolic channel

IP 4
10 marks

The cross-section of a straight canal is modelled by the curve \(y=\dfrac{x^2-16}{8}\) for \(-4\le x\le4\), where \(x\) and \(y\) are in metres and the bank tops are at \(y=0\).

  1. When the canal is full to the level \(y=0\), find the area of the water's cross-section.[3]
  2. The water flows at a uniform speed of \(0.6\) m/s. Find the volume of water passing a point each second.[2]
  3. In a dry spell the water level falls to \(y=-1\), so the depth halves from \(2\) m to \(1\) m. Find the new cross-sectional area exactly, and explain why it is much less than half the area in (a).[3]
  4. Real water flows more slowly near the bed and banks than at the centre. State how this affects your answer to (b).[2]

Solution:

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Answer:(a) \(\dfrac{32}{3}\approx10.7\text{ m}^2\) (b) \(6.4\text{ m}^3\) per second (c) \(\dfrac{8\sqrt2}{3}\approx3.77\text{ m}^2\), about \(35\%\), because the channel narrows towards the bottom (d) the flow in (b) is an overestimate

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