Solve the inequality \[\frac{(2x-1)(x+2)}{x-\frac{\sqrt3}{2}}\leq0.\][3]
Hence solve, in exact form, \[\frac{(2\sin\theta-1)(\sin\theta+2)}{\sin\theta-\frac{\sqrt3}{2}}\leq0,\qquad 0\leq\theta\leq2\pi.\][3]
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Answer:(i) \(x\in(-\infty,-2]\cup\left[\frac12,\frac{\sqrt3}{2}\right)\) (ii) \(\theta\in\left[\frac{\pi}{6},\frac{\pi}{3}\right)\cup\left(\frac{2\pi}{3},\frac{5\pi}{6}\right]\)