Divisibility from index laws

Divisibility from index laws

IP 2
9 marks

In this question \(n\) is a positive integer.

  1. Show that \(2^{n+2}-2^n\) is divisible by \(3\) for every \(n\).[2]
  2. Show that \(5^{n+1}+5^n\) is divisible by \(6\) for every \(n\).[2]
  3. Find the value of \(n\) for which \(3^{n+1}-3^{n-1}=216\).[3]
  4. Explain why \(2^n+2^{n+1}\) is never a multiple of \(5\), however large \(n\) is.[2]

Solution:

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Answer:(a) \(3\times2^n\) (b) \(6\times5^n\) (c) \(n=4\) (d) \(3\times2^n\) has no prime factor \(5\)

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