AB=sqrt((x_2-x_1)2+(y_2-y_1)2) For A(x_1,y_1) and B(x_2,y_2): Apply Pythagoras to the horizontal and

Question

AB=sqrt((x_2-x_1)2+(y_2-y_1)2) For A(x_1,y_1) and B(x_2,y_2): Apply Pythagoras to the horizontal and vertical changes. Distance is non-negative; reversing both subtraction orders gives the same result.

Accepted Answer

$AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Length of a Line Segment

Length of a Line Segment

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