A particle has s=t2-4t m, for 0 <= t 4. Then v=2t-4 m/s and a=2 m/s2. It reverses at t=2. Each graph below describes the same journey. Velocity–time: the gradient is acceleration. Signed area is displacement change; here the negative and positive triangular areas cancel. Speed–time: reflect negative velocity above the time axis. Area is distance, 4+4=8 m. Speed decreases before the turn and increases afterwards.
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