Angles in the Same Segment of a Circle: Equality Proofs
Angles in the Same Segment of a Circle: Equality Proofs
TGM Original
In the circle with centre \(O\), \(AD\) is a diameter.
The points \(B\) and \(C\) lie on the circumference of the circle such that \(\angle ADB = 28^\circ\) and \(\angle BDC = 42^\circ\).
Given that \(BCE\) is a straight line, find
- \(\angle ABD\),
- \(\angle BAC\),
- \(\angle DCE\).
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Answer:(a) \(90^\circ\) (b) \(42^\circ\) (c) \(62^\circ\)
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