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Problem involving Bearing

Problem involving Bearing

TGM Original

\(A\), \(B\) and \(C\) are three points on level ground.
The bearing of \(B\) from \(A\) is \(065{}^\circ\) and \(\angle ABC=30{}^\circ\).
It is given that \(C\) is \(4\) km due south of \(A\).
Calculate the

  1. bearing of \(C\) from \(B\),
  2. distance of \(BC\),
  3. shortest distance between \(A\) and \(BC\).

Solution:

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Answer:(i) \(215^\circ\) (ii) \(BC=7.25\text{ km}\text{ (3 s.f.)}\) (iii) \(2.29\text{ km}\text{ (3 s.f.)}\)

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