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Mixed Trigonometry: Altitude to Hypotenuse in \(PQR\)

Mixed Trigonometry: Altitude to Hypotenuse in \(PQR\)

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In \(\Delta PQR\), \(PQ=6.4\) m, \(\angle QPR=90{}^\circ \) and \(\angle PQR=71{}^\circ \). \(Y\) lies on \(QR\) such that \(PY\) is perpendicular to \(QR\).

Find the length of

  1. \(PY\),
  2. \(YR\).

Solution:

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Answer:(i) \(PY=6.05\text{ m}\) (ii) \(YR=17.6\text{ m}\)

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