Angles in an Isosceles Triangle with Parallel Lines
Angles in an Isosceles Triangle with Parallel Lines
TGM Original
In the figure, \(ABC\) is a straight line, \(AE=BE\) and \(AC//DE\). If \(\angle CBE=138{}^\circ \), find
- \(y\),
- \(x\),
stating your reasons clearly.
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Answer:(a) \(y=42^\circ\) (b) \(x=42^\circ\)
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