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Term-to-term and position rules

Term-to-term and position rules

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A sequence begins \(81,27,9,3,\ldots\), dividing by three at each step. State its term-to-term rule and nth term, then find its sixth term.

Solution:

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Answer:Divide by 3; \(T_n=81\left(\dfrac13\right)^{n-1}\); \(T_6=\dfrac13\).

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