A bag contains $10$ red balls, $10$ green balls and $6$ white balls. Two balls are drawn at ra

Question

A bag contains $10$ red balls, $10$ green balls and $6$ white balls. Two balls are drawn at random from the bag without replacement. What is the probability that they are of different colours?[4]

Accepted Answer

$P(\text{different})=1-\frac{\binom{10}2+\binom{10}2+\binom62}{\binom{26}2}=\frac{44}{65}$.

Calculate the probability of two different colours without replacement.

Calculate the probability of two different colours without replacement.

Solution:

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