For events $A$ and $B$, the probabilities are $P(A)=\frac3{11}$, $P(B)=\frac4{11}$. \(P(A\cu

Question

For events $A$ and $B$, the probabilities are $P(A)=\frac3{11}$, $P(B)=\frac4{11}$. $P(A\cup B)=\frac6{11}$. events A and B are independent.

Accepted Answer

(b) Under independence, $P(A\cap B)=\frac3{11}\frac4{11}=\frac{12}{121}$.

Calculate an intersection using the union rule and using independence.