Solve event probabilities using independence and the union rule.

Solve event probabilities using independence and the union rule.

6 marks
ProbabilityQuestionBank.pdf

The events A and B are independent such that \(P(B)\) = 3\(P(A)\) and \(P(A∪B)\) = 0.68. Find \(P(B)\)[6]

Solution:

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Answer:Let \(P(A)=a\), so \(P(B)=3a\). Independence gives \(0.68=4a-3a^2\). The admissible root is \(a=0.2\), so \(P(B)=0.6\).

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