A bag contains four apples $(A)$ and six bananas $(B)$. A fruit is taken from the bag and eaten.

Question

A bag contains four apples $(A)$ and six bananas $(B)$. A fruit is taken from the bag and eaten. Then a second fruit is taken and eaten. ________ $A$ ________ $B$ ________ $A$ ________ $B$ ________ $A$ ________ $B$ Complete the tree diagram below by writing probabilities in the spaces provided.[3] Find the probability that one of each type of fruit was eaten.[3]

Accepted Answer

$P(\text{one of each})=\frac4{10}\frac69+\frac6{10}\frac49=\frac8{15}$.

Complete a without-replacement fruit tree and calculate one-of-each probability.

Complete a without-replacement fruit tree and calculate one-of-each probability.

Solution:

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