A random variable X is distributed normally with a mean of 100 and a variance of 100. Find the value

Question

A random variable X is distributed normally with a mean of 100 and a variance of 100. Find the value of X that is 1.12 standard deviations above the mean. Find the value of X that is 1.12 standard deviations below the mean.

Accepted Answer

The standard deviation is $\sqrt{100}=10$. Therefore the required values are $100+1.12(10)=111.2$ and $100-1.12(10)=88.8$.

Convert fixed standard-deviation offsets into normal-variable values.

Convert fixed standard-deviation offsets into normal-variable values.

Solution:

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