The air inside an airtight syringe is compressed so that its volume, \(V\text{ cm}^3\), decreases.
The air pressure, \(P\) Newtons per \(\text{cm}^2\), within the syringe is inversely proportional to the volume so that \(PV=135\).
At a given time, the volume of air is \(20\text{ cm}^3\) and is decreasing at a rate of \(8\text{ cm}^3\) per minute.
Find the rate of increase in the air pressure at this time.[4]
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