IB Math HL January 2016 P2 Q5

IB Math HL January 2016 P2 Q5

8 marks
/Users/timgan/pCloud Drive/Tim Gan Math Learning Centre/Curriculum - IB/Resources - HL/Topical/REVISION 2 P2 (2016).pdf (PDF page 6, Paper 2 Question 5)

The sum of the first \(n\) terms of a sequence is given by \(S_n=\dfrac{3n^2}{2}-2n\).

  1. Express \(u_n\), the nth term of the sequence, in terms of \(n\).[3]
  2. Show that the sequence is arithmetic.[1]

It is given that

\[\sum_{r=n+1}^{2n}u_r=300+\sum_{r=1}^{n}u_r\]

  1. Find the value of \(n\).[4]

Solution:

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Answer:\(u_n=3n-\frac72\); common difference \(3\); \(n=10\).

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