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IB Math HL January 2016 P1 Q6
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IB Math HL January 2016 P1 Q6
8 marks
/Users/timgan/pCloud Drive/Tim Gan Math Learning Centre/Curriculum - IB/Resources - HL/Topical/REVISION 2 P1 (2016).pdf (PDF page 7-8, Paper 1 Question 6)
Show that \(\displaystyle \frac{1}{(k+2)!}-\frac{k+1}{(k+3)!}=\frac{2}{(k+3)!}\).
[1]
Prove by induction that for all positive integers \(n\),
\(\displaystyle \sum_{r=1}^{n}\frac{r\cdot2^r}{(r+2)!}=1-\frac{2^{n+1}}{(n+2)!}\)
[7]
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Answer:
The identity holds, and the stated summation formula is true for every positive integer \(n\) by induction.
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