Use position vectors relative to one origin. If \(A,B\) have position vectors \(\mathbf a,\mathbf b\), then \(\overrightarrow{AB}=\mathbf b-\mathbf a\). Equal displacement vectors give equal lengths and directions.
Midpoint theorem
In triangle \(ABC\), let \(M\) and \(N\) be the midpoints of \(AB\) and \(AC\).
\(\begin{aligned}\overrightarrow{MN}&=\dfrac{\mathbf a+\mathbf c}{2}-\dfrac{\mathbf a+\mathbf b}{2}\\&=\dfrac12(\mathbf c-\mathbf b)\\&=\dfrac12\overrightarrow{BC}.\end{aligned}\)
Thus \(MN\parallel BC\) and \(MN=\dfrac12BC\). To prove collinearity, express two displacement vectors from a common point as scalar multiples; to prove a parallelogram, show a pair of opposite directed sides is equal.
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