The Unit Circle and Related Angles

The Unit Circle and Related Angles

TGM Original

The point reached by an anticlockwise angle \(\theta\) on the unit circle is \((\cos\theta,\sin\theta)\). Clockwise angles are negative. Hence \(\tan\theta=\dfrac{\sin\theta}{\cos\theta}\), where \(\cos\theta\ne0\).

QuadrantPositive ratios
ISine, cosine and tangent
IISine
IIITangent
IVCosine

\(\sin(\pi-\theta)=\sin\theta,\quad\cos(\pi-\theta)=-\cos\theta,\quad\tan(\pi-\theta)=-\tan\theta\)

\(\sin(-\theta)=-\sin\theta,\quad\cos(-\theta)=\cos\theta,\quad\tan(-\theta)=-\tan\theta\)

A nonvertical line through the origin making angle \(\theta\) with the positive \(x\)-axis has gradient \(\tan\theta\) and equation \(y=x\tan\theta\). The angle is not itself the gradient.

For a point \(P(x,y)\ne O\) on the terminal ray, let \(r=\sqrt{x^2+y^2}>0\). Then \(\sin\theta=y/r\), \(\cos\theta=x/r\) and \(\tan\theta=y/x\) when \(x\ne0\). Keep the coordinate signs and use a positive radius.

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Need help? Join our JC Math tuition classes.

Learn more