Addition principle — count by different cases
Suppose a task can be completed by mutually exclusive plans \(A_1,A_2,\ldots,A_n\), with \(a_1,a_2,\ldots,a_n\) ways for the respective plans. Since exactly one plan is used, add the numbers of ways.
\[\sum\limits_{i=1}^{n}a_i=a_1+a_2+\cdots+a_n\]
Multiplication principle — count by different steps
Suppose a task is completed through successive steps \(B_1,B_2,\ldots,B_n\), with \(b_i\) available choices at step \(i\) for every allowed sequence of earlier choices. Multiply these numbers of choices. The choices need not be independent; the branch count at each step must be the same for every earlier choice.
\[b_1b_2\cdots b_n\]
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more