The graph shows $y=x^2-4x+3$. For each of $k=0$, $k=-1$ and $k=-2$, state the number of dist

Question

The graph shows $y=x^2-4x+3$. For each of $k=0$, $k=-1$ and $k=-2$, state the number of distinct real solutions of $x^2-4x+3=k$. Explain your answers using horizontal lines on the graph.[3]

Accepted Answer

$k=0$: 2; $k=-1$: 1; $k=-2$: 0.

How many intersections?

How many intersections?

Solution:

Solution locked