A harbour is at low tide of \(1.2\) metres at 1 pm on \(10^{\mathrm{th}}\) June 2025, and it next reaches a low tide at 11 pm on that day.
The tide level in the harbour, \(H\) metres, at a time \(t\) hours from noon on \(10^{\mathrm{th}}\) June 2025, can be modelled by the equation \(H(t)=a\cos\bigl(b(t-c)\bigr)+1.5\), where \(a\), \(b\) and \(c\) are real, positive constants and \(t\in\mathbb{R}\).
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more