N2013 P1 Q9

N2013 P1 Q9

Junior College 2
13 marks
  1. Prove by the method of mathematical induction that \[\sum_{r=1}^n r(2r^2+1)=\frac12n(n+1)(n^2+n+1).\][5]
  2. It is given that \(f(r)=2r^3+3r^2+r+24\). Show that \(f(r)-f(r-1)=ar^2\), for a constant \(a\) to be determined. Hence find a formula for \(\displaystyle\sum_{r=1}^n r^2\), fully factorising your answer.[5]
  3. Find \(\displaystyle\sum_{r=1}^n f(r)\). (You should not simplify your answer.)[3]

Solution:

Solution locked

Sign in to view the step-by-step solution

Finding similar questions...
Answer:(ii) \(a=6\), \(\sum_{r=1}^n r^2=\frac16n(n+1)(2n+1)\). (iii) \(\frac12n(n+1)(n^2+n+1)+\frac12n(n+1)(2n+1)+24n\).

Need help? Join our JC Math tuition classes.

Learn more