N2010 P2 Q4

N2010 P2 Q4

Junior College 2
11 marks

The function \(\mathrm f\) is defined as follows: \(\mathrm f:x\mapsto\frac1{x^2-1}\) for \(x\in\mathbb R\), \(x\ne-1\), \(x\ne1\).

  1. Sketch the graph of \(y=\mathrm f(x)\).[1]
  2. If the domain of \(\mathrm f\) is further restricted to \(x\ge k\), state with a reason the least value of \(k\) for which the function \(\mathrm f^{-1}\) exists.[2]

In the rest of the question, the domain of \(\mathrm f\) is \(x\in\mathbb R\), \(x\ne-1\), \(x\ne1\), as originally defined.

The function \(\mathrm g\) is defined as follows: \(\mathrm g:x\mapsto\frac1{x-3}\) for \(x\in\mathbb R\), \(x\ne2\), \(x\ne3\), \(x\ne4\).

  1. Show that \(\mathrm{fg}(x)=\frac{(x-3)^2}{(4-x)(x-2)}\).[2]
  2. Solve the inequality \(\mathrm{fg}(x)>0\).[3]
  3. Find the range of \(\mathrm{fg}\).[3]

Solution:

Solution locked

Sign in to view the step-by-step solution

Finding similar questions...
Answer:(ii) \(k=0\). (iv) \(2<x<3\) or \(3<x<4\). (v) \((-\infty,-1)\cup(0,\infty)\).

Need help? Join our JC Math tuition classes.

Learn more