One root of the equation \(x^4+4x^3+x^2+ax+b=0\), where \(a\) and \(b\) are real, is \(x=-2+\mathrm i\). Find the values of \(a\) and \(b\) and the other roots.[5]
Solution:
Solution locked
Sign in to view the step-by-step solution
Finding similar questions...
Answer:(i) \(3\pm5\mathrm i\). (ii) \(a=-16,b=-20\); other roots \(-2-\mathrm i,2,-2\).