A bank has an account for investors. Interest is added to the account at the end of each year at a fixed rate of 5% of the amount in the account at the beginning of the year. A man and a woman both invest money.
The man decides to invest \(\$x\) at the beginning of one year and then a further \(\$x\) at the beginning of the second and each subsequent year. He also decides that he will not draw any money out of the account, but just leave it, and any interest, to build up.
How much will there be in the account at the end of 1 year, including the interest?
Show that, at the end of \(n\) years, when the interest for the last year has been added, he will have a total of \(\$21(1.05^n-1)x\) in his account.
After how many complete years will he have, for the first time, at least \(\$12x\) in his account? You must show sufficient working to justify your answer.
The woman decides that, to assist her in her everyday expenses, she will withdraw the interest as soon as it has been added. She invests \(\$y\) at the beginning of each year. Show that, at the end of \(n\) years, she will have received a total of \(\$\frac1{40}n(n+1)y\) in interest.