Given that \(y=e^{\sqrt{1-x}}\), show that \[2\ln y\frac{\mathrm{d}^2y}{\mathrm{d}x^2}+\frac2y\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)^2=-\frac{\mathrm{d}y}{\mathrm{d}x}.\][2]
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