Show that \(\displaystyle \frac{\mathrm{d}y}{\mathrm{d}x}=\frac{2x-y}{x-2y}\).[2]
Hence find the exact \(x\)-coordinate of the points on \(C\) whose tangent is parallel to the \(x\)-axis.[3]
By finding the gradient of the tangent to \(C\) at \((0,1)\), hence find the acute angle between the tangent to \(C\) at \((0,1)\) and the \(x\)-axis.[2]
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