A particle has velocity v=(t-2)2 m,s-1 for 0 <= t 4 seconds. Sketch its speed–time and distance–time graphs, marking the rest time and endpoint values. Explain whether its distance graph has a maximum at rest.
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Answer:Speed \((t-2)^2\ \mathrm{m\,s^{-1}}\); distance \(D=\dfrac{t^3}{3}-2t^2+4t\) m. Rest at \(2\) s; distances \(0,\dfrac{8}{3},\dfrac{16}{3}\) m at \(0,2,4\) s. No distance maximum occurs at rest.